0=-0.016x^2+0.9x+6

Solution for 0=-0.016x^2+0.9x+6 equation:

0=-0.016x^2+0.9x+6

We move all terms to the left:

0-(-0.016x^2+0.9x+6)=0

We add all the numbers together, and all the variables

-(-0.016x^2+0.9x+6)=0

We get rid of parentheses

0.016x^2-0.9x-6=0

a = 0.016; b = -0.9; c = -6;
Δ = b2-4ac
Δ = -0.92-4·0.016·(-6)
Δ = 1.194
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.9)-\sqrt{1.194}}{2*0.016}=\frac{0.9-\sqrt{1.194}}{0.032}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.9)+\sqrt{1.194}}{2*0.016}=\frac{0.9+\sqrt{1.194}}{0.032}
$